Buster Exline: Math Question: The length of a rectangular garden is 9 feet longer than its width.? The length of a rectangular garden is 9 feet longer than its width. If the garden's perimeter is 198 feet, what is the area of the garden in square feet? w w+9 2w+9=99 2w=90 w=45 w+9=54 area=45*54=2430
Sammie Bocanegra: let the width of the rectangular garden = w feetthen the length of the rectangular garden = w + 14 feetperimeter of the rectangular garden is 2( w + w +14 ) = 4w + 28 feet so 4 w + 28 = 168 feet=> 4w = 140 => w = 35 feetthen length of the garden = 35 + 14 = 49 feet area of the garden = length * width = 49 * 35 = 1715 sq feet...Show more
Robin Tommie: complicated aspect. query in google. that could help!
Reyes Brunell: Area = 14 * iPerimeter = 2(14 + i) + 2(i)so simplify perimeter --> 28 + 2i + 2iperimeter = 28 + 4i = 168i = 35 feetso the garden is 35 feet by (14 + 35) feetArea = 35 * 49......Show more
Rick Duchane: Okay first thing is! to identify your variables;A=area= your answer and what you wantW= widthL = lengthP=PerimeterOkay now that you have that its just turning the sentences into equations. 9 out of 10 times the question will tell you everything you need to know and nothing extra so assume that if you haven't used all the numbers that your missing something. So what do you initially know before the problem?P=2L+2W which is a rectangleA=WLNow plug in the numbers from the question: P=168 and L=W+14so:168=2L+2W and L = W+1484=L+W (simplifying)84=(W+14) +W (substituting)84=2W +14 (simplifying)70=2W (simplifying)W=35 (simplifying)Plugging W back into L= W+14 and L =49 (substitution)A=WLA= 35*49A= 1715 ft^2...Show more
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